June will spin the arrow on the spinner 5 times. What is the probability that the arrow will stop on A, then B, then C, then D, then A?

Ok so assuming the board only has 4 spaces to land on (A, B, C, D) all we need to do is weight the probability,

1/4 x 1/4 x 1/4 x 1/4 x 1/4 = 1/1024

To solve I put the number of favorable outcomes over the number of total outcomes, in this case we had 1 favorable outcome each time and a constant of 4 possible outcomes.