Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is between 174 and 238? Round your answer to the nearest tenth of a percent.

A. 66.9%

B. 53.3%

C. 84.0%

D. 91.0%

Question

Mathematics

Campbell Davidson

3 February, 16:23

Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is between 174 and 238? Round your answer to the nearest tenth of a percent.

A. 66.9%

B. 53.3%

C. 84.0%

D. 91.0%

+2

Answers (1)

Know the Answer?

Stella Marsh · Answer 1

P (174 < x < 238) = P (x < 238) - P (x < 174) = P[z < (238 - 222) / 16] - P[z < (174 - 222) / 16] = P (z < 1) - P (z < - 3) = 0.84134 - 0.00135 = 0.83999 or 83.999%

Answer: 84.0% to the nearest tenth.

Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is between 174 and 238? Round your answer to the nearest tenth of a percent.A. 66.9%B. 53.3%C. 84.0%D. 91.0%

Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is between 174 and 238? Round your answer to the nearest tenth of a percent.

A. 66.9%

B. 53.3%

C. 84.0%

D. 91.0%