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8 February, 04:48

Solve the following system of equations and show all work.

y = - x^2 + 4

y = 2x + 1

+1
Answers (2)
  1. 8 February, 07:16
    0
    -x^2 + 4 = 2x + 1

    -x^2 - 2x + 4 - 1 = 0

    -x^2 - 2x + 3 = 0

    (x + 3) (-x + 1) = 0

    x + 3 = 0 - x + 1 = 0

    x = - 3 - x = - 1

    x = 1

    so x = - 3 and x = 1
  2. 8 February, 08:37
    0
    Set them equal since they both equatl y

    -x^2+4=2x+1

    add x^2-4 to both sides

    0=x^2+2x-3

    factor

    0 = (x-1) (x+2)

    set each to zero

    x-1=0

    x=1

    x+2=0

    x=-2

    x=1 or - 2

    sub them

    y=2 (1) + 1

    y=2+1

    y=3

    y=2 (-2) + 1

    y=-4+1

    y=-3

    x is 1 and y is 3 or

    x is - 2 and y is - 3

    solutions are

    (1,3) and (-2,-3)
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