Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.

A.) x = 6, solution is not extraneous

B.) x = 6, solution is extraneous

C.) x = 11, solution is not extraneous

D.) x = 11, solution is extraneous

Question

Mathematics

Armani Gaines

7 May, 03:35

Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.

A.) x = 6, solution is not extraneous

B.) x = 6, solution is extraneous

C.) x = 11, solution is not extraneous

D.) x = 11, solution is extraneous

+4

Answers (1)

Know the Answer?

Elena Hayes · Answer 1

Given: 2 √ (x - 5) = 2

Taking the square of both sides:

[ 2√ (x - 5) = 2]^2

4 (x - 5) = 4

x - 5 = 1

x = 6

Among the choices, the correct answer is A. x = 6, solution is not extraneous.

Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.A.) x = 6, solution is not extraneousB.) x = 6, solution is extraneousC.) x = 11, solution is not extraneousD.) x = 11, solution is extraneous

Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.

A.) x = 6, solution is not extraneous

B.) x = 6, solution is extraneous

C.) x = 11, solution is not extraneous

D.) x = 11, solution is extraneous