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5 July, 09:17

What proportion of a normal distribution is located between the mean and z = 1.40? ?

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  1. 5 July, 09:58
    0
    The cumulative probability up to z = 0 (the mean) is 0.5000.

    The cumulative probability up to z = 1.4 is 0.9192.

    Therefore the proportion between the mean and z = 1.40 is:

    0.9192 - 0.5000 = 0.4192.

    the answer is: 0.4192 or 41.92%.
  2. 5 July, 10:53
    0
    A vertical line drawn through a normal distribution at z = - 1.00 separates the distribution into two sections, the body and the tail.
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