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Mathematics
Norah Bradshaw
7 February, 19:25
Logbase3 (x-2) + log3 (x+6) = 2
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Jayson Clements
7 February, 21:34
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log₃ (x - 2) + log₃ (x + 6) = 2
log₃ ((x - 2) (x + 6)) = 2
log₃ (x (x + 6) - 2 (x + 6)) = 2
log₃ (x (x) + x (6) - 2 (x) - 2 (6)) = 2
log₃ (x² + 6x - 2x - 12) = 2
log₃ (x² + 4x - 12) = 2
3² = x² + 4x - 12
9 = x² + 4x - 12
- 9 - 9
0 = x² + 4x - 21
0 = x² + 7x - 3x - 21
0 = x (x) + x (7) - 3 (x) - 3 (7)
0 = x (x + 7) - 3 (x + 7)
0 = (x - 3) (x + 7)
0 = x - 3 or 0 = x + 7
+ 3 + 3 - 7 - 7
3 = x or - 7 = x
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