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7 February, 19:25

Logbase3 (x-2) + log3 (x+6) = 2

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  1. 7 February, 21:34
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    log₃ (x - 2) + log₃ (x + 6) = 2

    log₃ ((x - 2) (x + 6)) = 2

    log₃ (x (x + 6) - 2 (x + 6)) = 2

    log₃ (x (x) + x (6) - 2 (x) - 2 (6)) = 2

    log₃ (x² + 6x - 2x - 12) = 2

    log₃ (x² + 4x - 12) = 2

    3² = x² + 4x - 12

    9 = x² + 4x - 12

    - 9 - 9

    0 = x² + 4x - 21

    0 = x² + 7x - 3x - 21

    0 = x (x) + x (7) - 3 (x) - 3 (7)

    0 = x (x + 7) - 3 (x + 7)

    0 = (x - 3) (x + 7)

    0 = x - 3 or 0 = x + 7

    + 3 + 3 - 7 - 7

    3 = x or - 7 = x
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