Find the sum and product of the roots. 7x 2 - 3x - 9 = 0

7x^2-3x-9=0

applying the quadratic formula we get:

x=[-b+/-sqrt (b^2-4ac) ] / (2a)

x=[ - (-3) + / - sqrt ((-3) ^2-4*7 * (-9)) ] / (2*7)

x=[3+/-sqrt (9+252) ]/14

x=[3+/-sqrt162]/14

hence

x=[3+/-16.1555]/14

x=1.3682 or - 0.9396

thus the sum of the roots will be:

(1.3682 + (-0.9396)) = 0.4286

the product will be:

(1.3682) (-0.9396)

=-1.28556