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19 September, 00:50

Step by step how to factor:

2y^2+9y+9=0

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Answers (1)
  1. 19 September, 03:09
    0
    Use ac method

    for ax²+bx+c=0 when a≠1

    multiply a and c, let's call the product r

    what 2 numbesr multiply to get r and add to get b

    2y²+9y+9=0

    2*9=18

    wat 2 numbers multiply to get 18 and add to get 9

    3 and 6

    split it up to that

    2y²+3y+6y+9=0

    group

    (2y²+3y) + (6y+9) = 0

    factor

    y (2y+3) + 3 (2y+3) = 0

    undistribute

    (y+3) (2y+3) = 0

    set to zero

    y+3=0

    y=-3

    2y+3=0

    2y=-3

    y=-3/2

    y=-3 and - 3/2

    it's factored form is (x+3) (2x+3)
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