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13 April, 08:32

Find - 3a2 - b3 + 3c2 - 2b3 if a = 2, b = - 1, and c = 3

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  1. 13 April, 12:29
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    If a = 2, b = - 1 and c = 3

    -3a^2 - b^3 + 3c^2 - 2b^3 = - 3 (2) ^2 - (-1) ^3 + 3 (3) ^2 - 2 (-1) ^3 = - 3 (4) - (-1) + 3 (9) - 2 (-1) = - 12 + 1 + 27 + 2 = 18
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