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6 April, 01:26

Differentiate

/[/ln / sin^2 x/]

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  1. 6 April, 02:29
    0
    Y = ln {[sin (x) ]^2}

    use the chain rule

    y' = 1 / [sin (x) ]^2 * 2sin (x) * cos (x) = 2cos (x) / sin (x) = 2 cot (x)

    Answer: 2 cot (x)
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