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10 November, 17:09

What are the discontinues of the function f (x) = x^2 - 16/6x-24

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  1. 10 November, 17:36
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    The function f (x) = (x^2 - 16) / (6x - 24) is discontinuos at

    6x - 24 = 0

    6x = 24

    x = 4.
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