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14 November, 22:09

When x2+3x-4 is subtracted from x (x2+3x-2) what is the difference

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Answers (2)
  1. 14 November, 23:18
    0
    Assuming that the problem is (x^2+3x-4) - x (x^2+3x-2) then this would be simple ... simplifying XD

    here is the work for you:

    (x^2+3x-4) - x (x^2+3x-2)

    (x^2+3x-4) - (x^3+3x^2-2x)

    Final Answer: - x^3-2x^2+5x-4
  2. 15 November, 01:16
    0
    I'm assuming this is x^2 + 3x - 4 and x (x^2 + 3x - 2)

    1.) First distribute x (x^2 + 3x - 2) to get x^3 + 3x^2 - 2x.

    2.) Because you are subtracting all the terms from x^3 + 3x^2 - 2x, it's the same thing as distributing - 1 to x^2 + 3x - 4 and then adding it to x^3 + 3x^2 - 2x.

    3.) - 1 (x^2 + 3x - 4) = - x^2 - 3x + 4

    4.) Add (x^3 + 3x^2 - 2x) + (-x^2 - 3x + 4)

    5.) x^3 + 2x^2 - 5x + 4 is your final answer.
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