What is the solution to the system of equations? Using substitution method.

x=3y+5

x-4y=3

Subsitution

x=3y+5

x-4y=3

we know that x=3y+5 so subsitute 3y+5 for x in second equation

3y+5-4y=3

5-y=3

subtract 5 from both sides

-y=-2

multiply - 1

y=2

subistute 2 for y in first equationx=3y+5

x=3 (2) + 5

x=6+5

x=11

x=11

y=2

in (x, y) form

(11,2)