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13 January, 17:35

The standard form of the equation of a circle is (x-3) 2 + (y-1) 2=16.

What is the general form of the equation?

A - x2+y2-6x-2y-26=0

B - x2+y2+6x+2y+26=0

C - x2+y2-6x-2y-6=0

D - x2+y2+6x+2y-6=0

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  1. 13 January, 17:40
    0
    We know that

    the general form of the equation of a circle is

    ax² + by² + cx + dy + e = 0

    we have

    (x-3) ² + (y-1) ² = 16

    x ²-6x+9+y²-2y+1=16

    x²+y²-6x-2y-6=0

    the answer is the option

    C) x2+y2-6x-2y-6=0
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