The standard form of the equation of a circle is (x-3) 2 + (y-1) 2=16.

What is the general form of the equation?

A - x2+y2-6x-2y-26=0

B - x2+y2+6x+2y+26=0

C - x2+y2-6x-2y-6=0

D - x2+y2+6x+2y-6=0

We know that

the general form of the equation of a circle is

ax² + by² + cx + dy + e = 0

we have

(x-3) ² + (y-1) ² = 16

x ²-6x+9+y²-2y+1=16

x²+y²-6x-2y-6=0

the answer is the option

C) x2+y2-6x-2y-6=0