The constraints of a problem are listed below. What are the vertices of the feasible region?

X+3y≤6

4x+6y≥9

X≤0

Y≥0

1. (-3/2, 5/2), (9/4, 0), (6,0)

2. (0,0), (0, 3/2), (9/4, 0)

3. (0,0), (0,2), (6,0)

4. (0, 3/2), (0,2), (6,0), (9/4, 0)

it is A.) for e2020 because it has (-3/2,5/2)

When x+3y=6 and x=0, we have (0,2). When x+3y=6 and y=0, we have (6,0). When 4x+6y=6 and x=0, we have (0,1). When 4x+6y=6 and y=0, we have (3/2,0). When 4x+6y=6 and x=0, we have (0,1). When 4x+6y=6 and x+3y=6, we have (-3/2,5/2).