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31 July, 15:14

How do I find the horizontal and vertical asymptotes of f (x) = 2/x^2-2x-3?

Also would like to check if my x and y intercepts are correct.

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  1. 31 July, 15:39
    0
    I love doing this

    for a function p (x) / q (x)

    if degree of p (x)
    if degrees are equal, divide linear coefients

    horzontal assemtotes

    first simplify

    then set denom to zero and solve for x values

    so

    f (x) = 2 / (x^2-2x-3)

    less so HA=y=0

    doesn't cross HA

    VA, set denom to zer

    x^2-2x-3=0

    (x-2) (x-1) = 0

    HA, at x=1 and x=2

    xint, set y=0 and solve

    not applicatble, no xint

    yint, set x=0

    ying=-2/3

    HA is y=2, doesn't cross it

    VA's at x=1 and x=2

    no xint

    yint at (0,-2/3)
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