In how many different ways can a panel of 12 jurors and 2 alternates be chosen from a group of 17 prospective jurors?

Question

Mathematics

Paxton Schneider

22 July, 20:16

In how many different ways can a panel of 12 jurors and 2 alternates be chosen from a group of 17 prospective jurors?

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Answers (1)

Know the Answer?

Camilla Bradshaw · Answer 1

The answer is C (17,12) * C (5,2).

Explanation:

The 12 jurors from 17 prospective can be chosen in C17,12 ways.

That is: 17! / [12! (17 - 12) ! ] = (17*16*15*14*13) / (5*4*3*2*1) = 6188 ways

The 2 alternates are chosen from a group of 17 - 12 = 5. Thas is C5,2

C5,2 = 5! / (2! 3!) = 5*4 / 2 = 10

So, the total number of ways is 6188 * 10 = 61880 ways.

Answer: 61880.