Find the area of the triangle if 8 and 12 are a leg and hypotenuse.

This is a right triangle; In a right triangle the base and the height are the legs.

We have to calculate the other leg.

Pythagoras Theroem:

leg₁²+leg₂²=hypotenuse²

dа ta:

leg₁=8

hypotenuse=12

Therefore:

8²+leg₂²=12²

64+leg₂²=144

leg₂²=144-64

leg₂²=80

leg₂=√80=4√5

Area of a triangle = (base * height) / 2 = (leg₁*leg₂) / 2 = (8) (4√5) / 2=16√5

Answer: the area of this triangle would be 16√5 u²