Yuto left his house for bike ride at 10am. when riko left yuto was 5.25 miles along path. if yutos average speed was 0.25 mpm and rikos was 0.35mpm, over what time period in minutes, t, strting from when riko left will riko be behind yuto

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Mathematics

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23 July, 13:23

Yuto left his house for bike ride at 10am. when riko left yuto was 5.25 miles along path. if yutos average speed was 0.25 mpm and rikos was 0.35mpm, over what time period in minutes, t, strting from when riko left will riko be behind yuto

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Charlie Booker · Answer 1

- - When Riko left the house, Yuto was 5.25 miles ahead of her.

- - From the time she left the house, she gained (0.35 - 0.25) = 0.1 mile on Yuto

every minute ... closing the gap at the rate of 0.1 mile per minute.

- - If she can keep it up, she'll close the gap in (5.25 / 0.1) = 52.5 minutes.

- - Riko is behind her brother when 0 ≤ t < 52.5 minutes.