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19 March, 05:51

A chemist needs a 30% iron alloy. How many grams of a 70% iron alloy must be mixed with 16 grams of a 20% iron alloy to obtain the requiered 30% alloy?

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  1. 19 March, 06:06
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    Let x=grams of 70% alloy:

    0.70x+16*0.20=0.30 (x+16)

    0.70x=0.30x+4.8-3.2

    0.40x=1.6

    x=1.6/0.4=16/4=4g

    4 grams of 70% alloy are needed.
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