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15 June, 01:27

Tom drops a coin from the top of a building. Tom is 90 meters from the ground when he drops the coin. A) What is the height of the coin exactly 3 seconds after he releases the coin? B) When the coin hits the ground, how much time has passed from when it was dropped until impact with the ground?

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  1. 15 June, 02:19
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    Disregarding air friction, the distance traveled by an object due to gravity is : H = 0.5*g*t^2. g is the gravitational constant at the surface of earth.

    g = 9.81 m/s^2

    After 3 seconds, Distance =.5*9.81*9 = 44.15 meters traveled.

    Since it was dropped from a height of 90 meters, the current height is 90 - 44.15 = (a) 45.85 meters

    (b) It has to travel 90 meters to hit the ground. So we must find t

    Using the same equation

    t = (2*H/g) ^.5

    t = (2*90/g) ^.5 = 4.28 seconds until it hits the ground
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