Ask Question
27 October, 19:29

A train left a station at noon going at 40 mph. A second train left at 3 p. m. going in the same direction at 60 mph. At what time will the second train catch up with the first?

+1
Answers (2)
  1. 27 October, 22:30
    0
    Noon to 3 that is a 3 hour diffrence 40 miles in an hour and 60 miles in an hour that will be a 20mph difference.

    The distance that was traveled by the first train is 40

    The distance by the second is 60 it started 3 hours late

    40t=60

    40t=60180

    20t=180

    t=9

    The second train will catch up at 9.00 pm
  2. 27 October, 23:27
    0
    I think at 6pm he will get caught up, correct my calculations if im wrong.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A train left a station at noon going at 40 mph. A second train left at 3 p. m. going in the same direction at 60 mph. At what time will the ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers