Factorise

30y^2 - 33yz - 18z^2

Hello,

30y²-33yz-18z²=3 (5y+2z) (2y-3z)

Since

Let's assume u=y/z

30y²-33yz-18z²=3 (10y²-11yz-6z²)

=3z² ((10 (y/z) ²-11 (y/z) - 6)

=3z² * (10u²-11u-6)

=3z² * (5u+2) (2u-3)

=3z² * (5y/z+2) (2y/z-3) = 3z² (5y+2z) (2y-3z) / z²

=3 (5y+2z) (2y-3z)