A car leaving a stop sign accelerates constantly from a speed of 0 feet per second to reach a speed of 44 feet per second. The distance of the car from the stop sign, d, in feet, at time, t, in seconds can be found using this equation.

d=1.1t^2

What is the average speed of the car, in feet per second, between t=2, and t=5?

A. 5.5

B. 6.6

C. 7.7

D. 8.5

Question

Finn

1 March, 15:28

+1

Answers (1)

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Jeramiah Mendoza · Answer 1

D (2) = 1.1*4=4.4 ft

D (5) = 1.1*25=25.25 ft

ΔD=25.25-4.4=20.85 ft

Δt=5-2=3

V=ΔD/Δt=20.85/3=6.95 ft/s

average speed of the car is 6.95 ft/s