Ask Question
15 June, 00:44

Which polynomial function has a leading coefficient of 1 and roots (7 + i) and (5 - i) with multiplicity 1?

f (x) = (x + 7) (x - i) (x + 5) (x + i)

f (x) = (x - 7) (x - i) (x - 5) (x + i)

f (x) = (x - (7 - i)) (x - (5 + i)) (x - (7 + i)) (x - (5 - i))

f (x) = (x + (7 - i)) (x + (5 + i)) (x + (7 + i)) (x + (5 - i))

+3
Answers (1)
  1. 15 June, 04:33
    0
    All of them have leading coefient of 1

    roots of r1 and r2 have factors of

    (x-r1) and (x-r2)

    multiplicity 1 means that each factor doesn't repeat, it only appears once

    so

    roots (7+i) and (5-i)

    f (x) = (x - (7+i)) (x - (5-i)) should be the answer

    1st one is wrong, doesn't have roots

    2nd is wrong, doesn't have roots

    3rd has extra roots

    4th is wrong

    3rd one is right

    f (x) = (x - (7 - i)) (x - (5 + i)) (x - (7 + i)) (x - (5 - i))
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Which polynomial function has a leading coefficient of 1 and roots (7 + i) and (5 - i) with multiplicity 1? f (x) = (x + 7) (x - i) (x + 5) ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers