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13 January, 00:37

Equation 1 4y+1=x

equation 2 x=5y

solve the system of linear equations by substitution

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  1. 13 January, 00:47
    0
    The first given equation is:

    4y + 1 = x ... > equation I

    The second given equation is:

    2x = 5y ... > equation II

    Substitute with equation I in equation II to get the value of y as follows:

    2x = 5y

    2 (4y+1) = 5y

    8y + 2 = 5y

    8y - 5y = - 2

    3y = - 2

    y = - 2/3

    Substitute with the value of y in equation I to get the value of x as follows:

    x = 4y + 1

    x = 4 (-2/3) + 1

    x = - 5/3

    Based on the above calculations:

    x = - 5/3

    y = - 2/3
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