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19 February, 09:25

The height of a balloon is given by the fucntion

s (t) = - 960t^2+26400t, where t = hours since lift-off and s = feet. Find the velocity of the balloon 5 hours after lift off

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Answers (2)
  1. 19 February, 10:45
    0
    16800 metres

    Working

    i) Differentiate the given function to get the velocity function:

    ds/dt = = 1920t + 26400

    Then replace the value of t with 5 hours

    v (t) = - 1920 (5) + 26500

    v (t) = - 9600+26500

    V (5) = 16800 m
  2. 19 February, 12:44
    0
    V is slope of graph s-t

    v (t) = s' (t) = - 1920t + 26400

    v (5) = - 1920 (5) + 26400
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