Ask Question
31 May, 07:40

What are the zeros of p (m) = (m^2-4) (m^2+1) jmap?

+5
Answers (1)
  1. 31 May, 08:31
    +1
    (m^2 - 4) (m^2 + 1) = 0

    (m - 2) (m + 2) (m^2 + 1) = 0

    (m - 2) = 0 gives m = 2

    (m + 2) = 0 gives m = - 2

    m^2 + 1 = 0

    m^2 = - 1

    m = i, - i

    The zeros are - 2, 2, i, - i
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What are the zeros of p (m) = (m^2-4) (m^2+1) jmap? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers