A number, n, is added to 15 less than 3 times itself. The result is 101. Which equation can be used to find the value of n? 3n - 15 + n = 101 3n + 15 + n = 101 3n - 15 - n = 101 3n + 15 - n = 101

N

3*n = 3n

15 less than 3n = 3n - 15

n + (3n - 15) = 101

The equation is the first one 3n - 15 + n = 101 which is the same with what we got.

N is added to 15 less than 3 times itself result is 101

n is added (n+)

15 less than (-15)

3 times itself (3n)

result is 101 (=101)

so the n's are plusses and 15 is minus

the answer is 3n-15+n=101 (fyi, n=29)