A pebble is tossed from the top of a cliff. the pebble's height in feet is given by y (t) = - 16t2 6t 200, where t is the time in seconds. its horizontal distance in feet from the base of the cliff is given by d (t) = 5t.

Question

Mathematics

Deon Novak

6 April, 06:34

A pebble is tossed from the top of a cliff. the pebble's height in feet is given by y (t) = - 16t2 6t 200, where t is the time in seconds. its horizontal distance in feet from the base of the cliff is given by d (t) = 5t.

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Lucas Rodgers · Answer 1

To start, you'll need to figure out at what time the pebble hits the ground. To figure this out, we'll set the height equal to 0. So: - 16t^2 + 6t + 200=0 What do you get when you solve for t? You can use factoring or the quadratic formula