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18 November, 16:44

Find an equation of the line whose intercepts are twice those of the graph of 5y+2x=10.

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Answers (2)
  1. 18 November, 19:16
    0
    5y+2x=10 y = - 25 x+2 2 4 6 8 10 - 2 - 4 - 6 - 8 - 10 2 4 6 8 10 - 2 - 4 - 6 - 8 - 10 Let's solve for x. 5y + 2x = 10 Step 1: Add - 5y to both sides. 2x + 5y + - 5y = 10 + - 5y 2x = - 5y + 10 Step 2: Divide both sides by 2. 2x 2 = - 5y + 10 2 x = - 5 2 y + 5 Answer: x = - 5 2 y + 5
  2. 18 November, 20:06
    0
    X intercept is where the line crosses the x axis or where y=0

    y intercept is where the line crosses the y axis or where x=0

    so find x and y intercept

    yintercept, x=0

    5y=10

    y=2

    yint is (0,2)

    xint, y=0

    2x=10

    x=5

    xint is (5,0)

    double

    yint is (0,4) and yint is (10,0)

    ok, so we do

    y=mx+b

    m=slope

    b=yint

    givenyint=4

    y=mx+4

    when x=10, y=00 because we got (10,0)

    0=10m+4

    miinus 4 both sides

    -4=10m

    divide oth sides by 10

    -2/5=m

    the equation is y=-2/5x+4 or

    2/5x+y=4

    2x+5y=20
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