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21 December, 12:59

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the formula d = - 16t2 + 1,000. Use an inequatily equation to find for the interval of time taken by the object to reach the height greater than 300 feet above the ground

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  1. 21 December, 13:42
    0
    -16t^2 + 1000 > 300

    16t^2 < 1000 - 300

    16t^2 < 700

    t^2 < 700/16

    t^2 < 43.75

    t < 6.61
  2. 21 December, 16:22
    0
    Find where it equals 300

    300=-16t²+1000

    minus 1000 from both sides

    -700=-16t²

    divide both sides by - 16

    43.75=t²

    square root both sides

    6.614=t

    it took at 6.614 seconds to get to a height of 300 ft above the ground
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