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14 August, 14:21

Two number that have a sum of 45 twice the greater number is six more than 5 times the lesser number

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  1. 14 August, 15:04
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    The numbers will be X and Y with X being the lesser

    x+y=45

    2y=5x+6

    now use a subtraction method to solve

    x+y=45

    y=45-x

    2 (45-x) = 5x+6

    90-2x=5x+6

    -7*=-84

    x=12

    y=45-12

    y=33

    so, x=12 and y=33
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