Integrate f (xyz) = 8xz over the region in the first octant above the parabolic cylinder z = y^2 and below the paraboloid z = 8-2x^2-y^2.

Question

Mathematics

Christopher Goodwin

2 October, 07:05

Integrate f (xyz) = 8xz over the region in the first octant above the parabolic cylinder z = y^2 and below the paraboloid z = 8-2x^2-y^2.

+1

Answers (1)

Know the Answer?

Joey Blake · Answer 1

The integration of the function f (xyz) is 8xz over the region in the first octant above the paraboloib cylinder Z=Y^2 and below is the paraboloid z=8-2x^2-y^2 and the integration to this is ∫ π2 0 ∫20 ∫ 8 - r2 (cos2 θ+1) r2 sin2 θ 8 r3 cosθsinθdzdrd θ i hope you understand my answer