Three brothers have ages that are consecutive even integers the product of the first & third boys ages is 20 more than twice the seconds boy age. find the age of each of the boys

Let's say X is the first brother's age

x+2 is second brother, and x+4 is the third brother

Since the product of the first and third boy x (x+4) is 20 more than twice (20+x (x+2), our equation is x (x+4) = 20+2 (x+2)

Simplify from there and see what you get.