David is standing 5000 feet away from the base of a cell phone tower. The angel of elevation from his eyes to the top of the tower is 78 degrees. If David's eyes are 6 feet above the ground how y'all is the tower?

To solve this proble you must apply the proccedure shown below:

1. You have that:

- David is standing 5000 feet away from the base of a cell phone tower. and the angel of elevation from his eyes to the top of the tower is 78 degrees.

- David’s eyes are 6 feet.

2. Therefore, you have:

Tan α=opposite/adjacent

Tanα=x/5000

x = (5000) (Tan (78°))

x=23,523.15 feet

3. Then, you have that the height of the tower is:

h=6 feet+23,523.15 feet

h=23,529.15 feet

The answer is:23,529.15 feet