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2 November, 22:39

Find the set the solves

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Answers (1)
  1. 3 November, 01:07
    0
    Hello,

    To exist x≠0

    if x>0 then

    x+2/x>=3==>x²+2>=3x

    ==>x²-3x+2>=0

    ==> (x-2) (x-1) >=0 positive out of the roots

    ==> (x=2) and x>0

    ==> (0
    else

    x<0

    x+2/x>=3==>x²+2<=3x

    ==>x²-3x+2<=0 negative betheen the roots

    ==> (1<=x<=2) and x<0 : no solution

    end if
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