Suppose there are three blue marbles and three yellow marbles in a bag and you want to remove two marbles. You do not replace the first marble. What is the probability that you will select a blue marble and then a yellow marble? Express your answer as a percent

Total sample space {b, b, b, y, y, y,} = > (3blues + 3 yellows) = all possible outcome

P (1st draw = b) = 3/6 = 1/2 = 0.5 or 50%

Since it's not replaced, the sample space becomes {b, b, y, y, y}

P (2nd draw=y) = 3/5 = 0.6 = 60%

Now the probability of drawing a blue AND a yellow (blue ∩yellow), becomes a conditional probability that means P (b∩y) = p (b) x P (y)

P (blue AND yellow) = 0.5 x 0.6 = 0.3