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Mathematics
Abram Middleton
7 May, 12:10
Find f (x+deltax) for f (x) = x^2 - 2x-3
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Genesis Walls
7 May, 14:47
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Let be Dx = deltax
if f (x) = x^2 - 2x-3, so f (x + Dx) = (x + Dx) ² - 2 (x + Dx) - 3=x² + D²x + 2x. Dx - 2x - 2Dx - 3
f (x + Dx) = x² + D²x + 2 (x - 1) Dx - 2x - 3
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