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19 June, 18:05

Y = (x^2-6x+14) Labeling the vertex

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  1. 19 June, 20:09
    0
    I leaerned this neat trick

    you don't need to convert to vertex form

    where

    y=ax^2+bx+c

    the x value of the vertex is - b/2a

    the y value is found by inserting the x value of the vertex into the equation

    so

    1x^2-6x+14

    -b/2a = - (-6) / 2 (1) = 6/2=3

    plug that in

    y=x^2-6x+14

    y=3^2-6 (3) + 14

    y=9-18+14

    y=5

    the vertex is (3,5)
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