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Mathematics
Sarahi Atkinson
19 June, 18:05
Y = (x^2-6x+14) Labeling the vertex
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Princess Beasley
19 June, 20:09
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I leaerned this neat trick
you don't need to convert to vertex form
where
y=ax^2+bx+c
the x value of the vertex is - b/2a
the y value is found by inserting the x value of the vertex into the equation
so
1x^2-6x+14
-b/2a = - (-6) / 2 (1) = 6/2=3
plug that in
y=x^2-6x+14
y=3^2-6 (3) + 14
y=9-18+14
y=5
the vertex is (3,5)
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