Carmen Enters a painting in an art contest. The contest rules ssay that all paintings must be rectangular, with an area no greater than 3,00.04 cm2. Carmen's painting is 16 cm wide. What is the greatest length the painting can have and still have an area within the contest rules?

Hint: A rectangle's area is the product of the width and the length

Question

Mathematics

Sierra Rogers

7 August, 15:31

Carmen Enters a painting in an art contest. The contest rules ssay that all paintings must be rectangular, with an area no greater than 3,00.04 cm2. Carmen's painting is 16 cm wide. What is the greatest length the painting can have and still have an area within the contest rules?

Hint: A rectangle's area is the product of the width and the length

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Answers (1)

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Viviana Stephens · Answer 1

Given:

Rectangle shaped canvas.

Area = 3,003.04 cm²

Width = 16 cm

Area of a rectangle = length * width

3,003.04 cm² = length * 16 cm

3,003.04 cm² / 16 cm = length

187.69 cm = length

The greatest length the painting can have is 187.69 cm.