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25 January, 07:31

What is the period and frequency of a 10-pound weight oscillating (as a pendulum) on a 5-meter-long rope?

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  1. 25 January, 07:55
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    The mass of the pendulum does not affect the period and frequency

    The period can be determined using the formula:

    T = 2π √ (L/g)

    where L is the length of the rope

    and g is the acceleration due to gravity = 9.8 m/s2

    Plugging in the values:

    T = 2π √ (5/9.8)

    T = 10π/7 = 4.49 s

    And for the frequency:

    f = 1/T

    f = 1/4.49

    f = 0.22 Hz
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