What is the vertex of y=-x^2-3x+6

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Mathematics

Snowy

15 August, 07:58

What is the vertex of y=-x^2-3x+6

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Angel Wall · Answer 1

Since the x value of the vertex is - b/2a in ax^2+bx+c, we have - 3 as b and - 1 and a, getting - (-3/-1*2) = - (3/2) = - 3/2 as the x value of the vertex. To get the y value of the vertex, we plug the x value of the vertex into the function, resulting in - (3/2) ^2-3 * (-3/2) + 6=8.25, making the vertex (-3/2, 8.25)