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23 June, 04:03

Solve for the system of linear equations x+y=4 2x+3y=0

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Answers (2)
  1. 23 June, 04:41
    0
    Solve x+y=4 for x

    x+y+-y=4+-y (add - y to both sides)

    x=-y+4

    substitute - y+4 for x in 2x+3y=0

    2x+3y=0

    2 (-y+4) + 3y=0

    y+8=0 (simplify both sides of the equation)

    y+8+-8=0+-8 (add - 8 to both sides)

    y=-8

    substitute - 8 for y in x=-y+4:

    x=-y+4

    x = - (-8) + 4

    x=12 (simplify both sides of the equation)

    answer is x=12 and y=-8
  2. 23 June, 07:07
    0
    X+y=4

    2x+3y=0

    x=4-y

    2 (4-y) + 3y=0

    8-2y+3y=0

    8+y=0

    y=-8

    x + (-8) = 4

    x-8=4

    x=12
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