If i^2=-1 and (4+2i) (6-ki) = 30, what is the value of k?

I^2 = - 1

i = √-1

Substitute the value of i in the equation:

(4+2i) (6-ki) = 30

{4 + (2) (√-1) } {6 - k (√-1) } = 30

(4 + 2√-1) (6 - k√-1) = 30

24 - 4k√-1 + 12√-1 - 2k (-1) = 30

24 - 4k√-1 + 12√-1 + 2k = 30

-4k√-1+12√-1 + 2k - 6 = 0

-2√-1 (2k - 6) + (2k-6) = 0

(-2√-1 + 1) (2k-6) = 0

2k - 6 = 0

2k = 6

k = 3

So, the value of k is 3.