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19 August, 23:40

Y varies jointly as x and √z. If y = 6 when x = 3 and z = 9, find y when x = 4 and √z = 3.6.

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  1. 19 August, 23:57
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    Y = kx√z where k is some constant

    To find the value of k we plug in the given values of x, y and z:-

    6 = k*3*√9

    6 = k*3*3

    9k = 6

    k = 6/9 = 2/3

    so the relation is y = (2/3) x√z

    When x = 4 and √z = 3.6 we have:-

    y = (2/3) * 4 * 3.6

    = 9.6 Answer
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