A school is building a rectangular soccer field that has a perimeter of 340 yards. the soccer field must be 50 yards longer than its width? a. create a let statement and an equation for the given situation?

b. solve your equation to find the length and width of the field in yards

A. Let

L = length of a rectangular soccer field

W = width of a rectangular soccer field

P = perimeter of a rectangular soccer field

L = W + 50 (the length is longer than the width)

For the equation, the formula for a perimeter of the rectangle is

2L + 2W = P

Since the length and perimeter are given, substitute them as

2 (W + 50) + 2W = 340

b. Solving for W,

2 (W + 50) + 2W = 340

2W + 100 + 2W = 340

2W + 2W = 340 - 100

4W = 240

(4W) / 4 = 240/4

W = 60 yards

Solving for L,

L = 60 + 50 = 110 yards

The rectangular soccer field has the length of 110 yards and the width of 60 yards.