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26 September, 17:46

Law of cosines: a2 = b2 + c2 - 2bccos (A) Find the measure of Q, the smallest angle in a triangle whose sides have lengths 4, 5, and 6. Round the measure to the nearest whole degree.

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  1. 26 September, 18:28
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    We are tasked to solve for the smallest angle using the law of cosines given that the three sides of the triangle are 4,5 and 6.

    a=4, b=5, c=6

    Angle 1:

    cosA = 5² + 6² - 4² / 2*5*6

    A=41.41°

    Angle 2:

    cos B = 4²+6² - 5² / 2*4*6

    B = 55.77°

    Angle C:

    C = 180° - 41.41° - 55.77°

    C = 82.82°

    The smallest angle is A which is equal to 41.41°.
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