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Mathematics
Camille Stuart
18 March, 08:45
TanA+tanB=sin (A+B) / cosAcosB
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Raphael Patel
18 March, 10:46
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Do you need to prove that it is equal?
If so:
SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA) / cosAcosB
(SinAcosB + sinBcosA) / cosAcosB = (SinAcosB + sinBcosA) / cosAcosB
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