A right cylindrical container perfectly holds 5 tennis balls placed one above the other. The radius of each ball is 3.35 centimeters. What is the approximate volume of the unoccupied space in the container?

Answer = Cylinder Volume - 5 (1 of the ball's volume)

Cylinder Volume: (pi) (r^2) (h)

Sphere Volume: 4/3 (pi) (r^3)

Total of the Tennis balls' volume = 787.4

Total Volume of Cylinder = 590.55

I think 196.85 is the space left? I might've made an error ...